Optimal. Leaf size=79 \[ \frac{2 a \tanh ^{-1}\left (\frac{\sqrt{c-d} \tan \left (\frac{1}{2} (e+f x)\right )}{\sqrt{c+d}}\right )}{f \sqrt{c-d} (c+d)^{3/2}}+\frac{a \tan (e+f x)}{f (c+d) (c+d \sec (e+f x))} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.139065, antiderivative size = 79, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.172, Rules used = {4003, 12, 3831, 2659, 208} \[ \frac{2 a \tanh ^{-1}\left (\frac{\sqrt{c-d} \tan \left (\frac{1}{2} (e+f x)\right )}{\sqrt{c+d}}\right )}{f \sqrt{c-d} (c+d)^{3/2}}+\frac{a \tan (e+f x)}{f (c+d) (c+d \sec (e+f x))} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 4003
Rule 12
Rule 3831
Rule 2659
Rule 208
Rubi steps
\begin{align*} \int \frac{\sec (e+f x) (a+a \sec (e+f x))}{(c+d \sec (e+f x))^2} \, dx &=\frac{a \tan (e+f x)}{(c+d) f (c+d \sec (e+f x))}-\frac{\int \frac{a (c-d) \sec (e+f x)}{c+d \sec (e+f x)} \, dx}{-c^2+d^2}\\ &=\frac{a \tan (e+f x)}{(c+d) f (c+d \sec (e+f x))}+\frac{a \int \frac{\sec (e+f x)}{c+d \sec (e+f x)} \, dx}{c+d}\\ &=\frac{a \tan (e+f x)}{(c+d) f (c+d \sec (e+f x))}+\frac{a \int \frac{1}{1+\frac{c \cos (e+f x)}{d}} \, dx}{d (c+d)}\\ &=\frac{a \tan (e+f x)}{(c+d) f (c+d \sec (e+f x))}+\frac{(2 a) \operatorname{Subst}\left (\int \frac{1}{1+\frac{c}{d}+\left (1-\frac{c}{d}\right ) x^2} \, dx,x,\tan \left (\frac{1}{2} (e+f x)\right )\right )}{d (c+d) f}\\ &=\frac{2 a \tanh ^{-1}\left (\frac{\sqrt{c-d} \tan \left (\frac{1}{2} (e+f x)\right )}{\sqrt{c+d}}\right )}{\sqrt{c-d} (c+d)^{3/2} f}+\frac{a \tan (e+f x)}{(c+d) f (c+d \sec (e+f x))}\\ \end{align*}
Mathematica [A] time = 0.225903, size = 75, normalized size = 0.95 \[ \frac{a \left (\frac{\sin (e+f x)}{c \cos (e+f x)+d}-\frac{2 \tanh ^{-1}\left (\frac{(d-c) \tan \left (\frac{1}{2} (e+f x)\right )}{\sqrt{c^2-d^2}}\right )}{\sqrt{c^2-d^2}}\right )}{f (c+d)} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 0.089, size = 105, normalized size = 1.3 \begin{align*} 4\,{\frac{a}{f} \left ( -1/2\,{\frac{\tan \left ( 1/2\,fx+e/2 \right ) }{ \left ( c+d \right ) \left ( \left ( \tan \left ( 1/2\,fx+e/2 \right ) \right ) ^{2}c- \left ( \tan \left ( 1/2\,fx+e/2 \right ) \right ) ^{2}d-c-d \right ) }}+1/2\,{\frac{1}{ \left ( c+d \right ) \sqrt{ \left ( c+d \right ) \left ( c-d \right ) }}{\it Artanh} \left ({\frac{\tan \left ( 1/2\,fx+e/2 \right ) \left ( c-d \right ) }{\sqrt{ \left ( c+d \right ) \left ( c-d \right ) }}} \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [B] time = 0.509431, size = 780, normalized size = 9.87 \begin{align*} \left [\frac{{\left (a c \cos \left (f x + e\right ) + a d\right )} \sqrt{c^{2} - d^{2}} \log \left (\frac{2 \, c d \cos \left (f x + e\right ) -{\left (c^{2} - 2 \, d^{2}\right )} \cos \left (f x + e\right )^{2} + 2 \, \sqrt{c^{2} - d^{2}}{\left (d \cos \left (f x + e\right ) + c\right )} \sin \left (f x + e\right ) + 2 \, c^{2} - d^{2}}{c^{2} \cos \left (f x + e\right )^{2} + 2 \, c d \cos \left (f x + e\right ) + d^{2}}\right ) + 2 \,{\left (a c^{2} - a d^{2}\right )} \sin \left (f x + e\right )}{2 \,{\left ({\left (c^{4} + c^{3} d - c^{2} d^{2} - c d^{3}\right )} f \cos \left (f x + e\right ) +{\left (c^{3} d + c^{2} d^{2} - c d^{3} - d^{4}\right )} f\right )}}, \frac{{\left (a c \cos \left (f x + e\right ) + a d\right )} \sqrt{-c^{2} + d^{2}} \arctan \left (-\frac{\sqrt{-c^{2} + d^{2}}{\left (d \cos \left (f x + e\right ) + c\right )}}{{\left (c^{2} - d^{2}\right )} \sin \left (f x + e\right )}\right ) +{\left (a c^{2} - a d^{2}\right )} \sin \left (f x + e\right )}{{\left (c^{4} + c^{3} d - c^{2} d^{2} - c d^{3}\right )} f \cos \left (f x + e\right ) +{\left (c^{3} d + c^{2} d^{2} - c d^{3} - d^{4}\right )} f}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} a \left (\int \frac{\sec{\left (e + f x \right )}}{c^{2} + 2 c d \sec{\left (e + f x \right )} + d^{2} \sec ^{2}{\left (e + f x \right )}}\, dx + \int \frac{\sec ^{2}{\left (e + f x \right )}}{c^{2} + 2 c d \sec{\left (e + f x \right )} + d^{2} \sec ^{2}{\left (e + f x \right )}}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [B] time = 1.70837, size = 193, normalized size = 2.44 \begin{align*} -\frac{2 \,{\left (\frac{{\left (\pi \left \lfloor \frac{f x + e}{2 \, \pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (2 \, c - 2 \, d\right ) + \arctan \left (\frac{c \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) - d \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )}{\sqrt{-c^{2} + d^{2}}}\right )\right )} a}{\sqrt{-c^{2} + d^{2}}{\left (c + d\right )}} + \frac{a \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )}{{\left (c \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} - d \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} - c - d\right )}{\left (c + d\right )}}\right )}}{f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]